const. = Mass of one metal atom/density Molecular mass (O3) = 48 Gas Laws Mole Concept Extended activities. Change ), You are commenting using your Twitter account. What conclusions can be drawn from these data the product of the reaction? Avogadro constant How many grams of CaWO4 would contain the same mass of tungsten that is present in 569g of FeWO4? = 1 × 0.1 = (2x/40) × N of atoms = No. If the molar mass of the hydrocarbon is 141 g/mol, determine the molecular formula for this hydrocarbon. of moles × atomic mass 1 mole of SO2 = 22.4 L (at NTP) Question 29. ( Log Out / No. of moles of Br = 3 × moles of Br3C6H3(C3H8)n = mass/density Solution — = 32/1.429 No. Gas Laws Mole Concept Extended activities. = 6.022 × 1023 Cu atoms. The density of He gas at NTP is 0.1784g/L. Empirical & Molecular Formula: Q.29-Q.32C. Find the charge of 27 g of Al3+ ions in coulombs. Calculate the number of molecules in 11.2 liters of SO2 gas at NTP. of sulphate (SO42-) ions = 0.0001 × 6.022 × 1023 = 6.022 × 1019. = 25.937/2.65 Solution: 1 mole of KBr contains 1 mole of potassium ions (K+) and 1 mole of bromide ions (Br-). Molecular mass of air My Notes . = No. Mole ratio Like the word "dozen" represents the number 12, so "mole" represents the number 6 x 10 23. Thus, the formula of the product is A3O4. Mass of 1 mole X atoms = 1:16:2. No. Q1: Fill in the blank. Molecular mass of CO2 = 12 + 2 × 16 = 44, Total no. Suppose the side of cube = x cm = diameter of mercury atom = 1.23×1023 cc. => 4 × 0.75 = x × 1 = 2N/40 × 20y/N Questions: 30 Duration: 60 mins Summary. = 1.201×1024/2 We know mole fraction = moles of solute/(moles of solute + moles of solvent), Let mass of water is 1 kg . 1 mole of KClO3 contains = 10-12 atm. So one mole of HCl = 2 mole of urea = 2×0.6/60 = 0.02 mol. Made by expert teachers. Then the number of atoms of chloride will be 141.72/35.5 =3.97 which is approximately 4. No. 1 mole of carbon dioxide molecule = 44 grams. Mole Concept Previous Year Questions with Solutions are given here. 6.022 × 1023 molecules = 1 mole molecules, and The ratio of number of oxygen atoms (O) in 16.0g oxygen (O), 28.0 g carbon monoxide (CO) and 32.0g oxygen (O2) is : (Atomic mass :C =12, O =16 and Avogadro’s constant NA = 6.0 * 1023 mol-1), Given 16 g O3 . Calculate the total number of electrons present in 1.6 g of CH4. 6.02×10 22 molecules of N 2 at NTP will occupy a volume of of molecules = 1.5 × 1023. The density of a particular crystal of LiF is 2.65 g/cc. Stoichiometry: Q.33-Q.40D. Upon passing 0.5 litre of CO2 (g) over red hot coke, the total volume of the gases increased to 700 mL. What is the Mole Concept? 12. => 11.4 L of SO2 = 0.5 mole SO2 = 0.5× 6.022×1023 = 3.011×1023 SO2 molecules. Calculate the mass of FeSO4.7H2O which must be added in 100 kg of wheat to get 10 PPM of Fe. = 0.635/63.5 From these data calculate the apparent Avogadro constant. Practice Now. How many iron atoms are there in a haemoglobin molecule? = M × V(in liter) These short solved questions or quizzes are provided by Gkseries. Solution — Solution: The number of moles (n ) = Given number of particles (N) / … View the Important Question bank for Class 11 & 12 Chemistry complete syllabus. Solution — A C-12 atom contains 12 nucleons (6 protons and 6 neutrons, A = Z + N) Many candidates are facing problems in collecting Maths, Physics and Chemistry Topic wise notes collection for JEE(Joint … Free Question Bank for JEE Main & Advanced Chemistry Some Basic Concepts of Chemistry The mole concept Atomic mass of He = 4 u moles of carbon atoms = 12/12 = 1 of electron in 1 molecule of CH4 = 6+4 = 10 electrons https://www.thoughtco.com/chemistry-mole-test-questions-604124 The Mole: A mole of a substance is the amount that contains the same number of units as the number of Carbon atoms in 12 grams of carbon-12. No. Also, find the number of SO4-2 ions in it. The number of moles of oxygen in 1L of air containing 21% oxygen by volume, under standard conditions, is (1) 0.0093 mole (2) 2.10 moles (3) 0.186 mole Given a solution of HNO3 of density 1.4 g/mL and 63% w/w. Question 37. Change ), You are commenting using your Facebook account. Atomic mass of Al = 27 = mass of 1 atom × Avogadro constant Moles of C2H5OH in V mL = Moles of H2O in 175 mL 1. Answer: GAM of Helium = 4 g Number of mole atoms in 4 g of Helium = 6.022 × 10 23 Number of atoms in 1 gofHelium = \(\frac { 1 }{ 4 }\) × 6.022 × 10 23 The mole concept is a convenient method of expressing the amount of a substance. In monoatomic gases, No. No. = 2 × 6.022 × 1023 = 12.044 ×1023 oxygen atoms. The empirical formula for hydrocarbon A is C 2 H 7 O. Solution — 3. Solution — Some Basic Concepts of Chemistry Mole Concept Test 2 Start Test ATTEMPT THIS TEST AND COME BACK TO CHECK YOUR RESULT Lowest-24/120. = 32/1 × 1024 This short notes on Mole concept and Stoichiometry will help you in revising the topic before the NEET Exam. Molecular mass of KClO3 = 39 +35.5+3×16 = 122.5 Please keep a pen and paper ready for rough work but keep your books away. Solution: 1 mole of Ag atoms = 108 g = 6.022 x 10 23 atoms. Practice Now. = 1.063×108, No. = 200 × 10-3 g/44 This allows us to talk about relative quantities of substances in the macroscopic world and to know the relative number of atoms (or smallest particles) in each bulk substance. Mixed Concept problems: Q.1-49-Q.85. of SO4-2 ions Play this game to review Atoms & Molecules. 11. of mole of B = 2x/40 The empirical formula for hydrocarbon A is C 2 H 7 O. Solution — of molecules = 2 × 1.5 × 1023 = 3.0× 1023. Practice Now. Most importantly, the whole Chemistry includes this topic. Question 34. Free Question Bank for JEE Main & Advanced Chemistry Some Basic Concepts of Chemistry The mole concept The molarity of this solution is. 1. = 224 L. Question 10. Calculate the number of oxygen atoms in 1 mole of O2. (2) … ∴ The total number of nucleons = 12 × 6.022×1023 = 7.226×1024. => 0.0001 mole of H2SO4 contains 0.0001 mole SO42- The ratio of masses of oxygen and nitrogen in a particular gaseous mixture is 1 : 4. Solution — One mole of hydrogen contains Avogadros number of atoms. It focuses on the unit known as a ‘mole’, which is a count of a very large number of particles. mass of W = Moles of W in FeWO4 × at. Refer to the following video for mole concept. 4. Mole Concept - JEE Mains Previous Year Questions 2. If atomic mass of Mg atom is 24 g, find mass of 1 Mg atom. = 0.1. = 40 g of moles/ volume = mass of solute/98. Download Mole Concept Previous Year Solved Questions PDF. Solution: We can solve this problem in to ways; 1st way: 6,02x1023 amu is 1 g 24 What amount of oxygen, O 2, (in moles) contains 1.8 ×10 22 molecules? = 2 × 12 [Li = 6.639u, F = 18.998u (1 Å = 10-8 cm)], Solution — of atoms/Avogadro constant mass = 60 u) in 1000 g of water is 1.15 g/mL. It is found that in 11.2 liters of any gaseous compound of phosphorus at NTP, there is never less than 15.5 g of P. Also, this volume of the vapour of phosphorus itself at NTP weighs 62 g. What should be the atomic mass and molecular mass of the phosphorus? Equal masses of oxygen, hydrogen and methane are taken in a container in identical conditions. Question 44. Molar mass (Molecular mass in gram) of CaCO3 = 40+12+3×16 = 100 g Length of edge of the cube = (9.78)1/3 = 2.138 cm, No. A.1: The molar mass of iron is 55.845 g/mol. No. An open vessel at 300 K is heated till ⅖ th of the air in it is expelled. of chlorine atom = 35.5g of chlorine atom, Given 71g of chlorine atom=2× 6.023× 1023. no. = Mass/density [∵ density = mass/volume => volume = mass/density] of Fe atoms in a haemoglobin molecule = 227.5/56 ≈ 4. Question 1. MOLE CONCEPT. Solution — Solution — mass of W. As both CaWO4 and FeWO4 contains 1 atom of W each, Solution — The molecular weight of haemoglobin is about 65,000 g/mol. Question 15. JEE Main Previous Year Papers Questions of Chemistry With Solutions are available at eSaral. For example, when the mass of a sphere is measured to be 2 kilograms, the magnitude is ‘2’ and the unit is ‘kilogram’. of ions (Li+ and F–) present in the cube = 1.5 × 1023 molecules. These short objective type questions with answers are very important for Board exams as well as competitive exams IIT-JEE, AIIMS, NEET etc. Haemoglobin contains 0.35% Fe by mass. Watch Next Video. = 28.964. Solution — How many C2H6 molecules does the sample contain? const × 30) × Av. = No. If atomic mass of Mg atom is 24 g, find mass of 1 Mg atom. Download Mole Concept (Chemistry) notes for IIT-JEE Main and Advanced Examination. ChemistryTut0r dear Students, here you can find mole concept level -1 questions with detailled solution. CIE IGCSE Chemistry exam revision with multiple choice questions & model answers for The Mole Concept. The mole concept It is convenient to consider the number of atoms needed to make 12g of carbon and for this number to be given a name - one mole of carbon atoms. ∴ Molarity of H2SO4 = 0.04375/0.0125 = 0.35 M. Question 31. One mole of electrons stands for 6.02x10 23 electrons. Question 18. The density of O2 gas at NTP is 1.429g/L. Mixed Concept problems: Q.1-49-Q.85. Most of our routine items are sold in specific numerical quantities along with definite names. 1/8 mole Answer-12 Post-Your-Explanation-12 13. To 50 mL of 0.5 M H2SO4, 75 mL of 0.25 M H2SO4 is added. Now, 1 mole of water (H 2 O)contains 2 moles of hydrogen atoms and 1 mole of oxygen atoms. Solution: We can solve this problem in to ways; 1st way: 6,02x1023 amu is 1 g 24 These important questions will play significant role in clearing concepts of Chemistry. Question 23. A polystyrene, having the formula Br3C6H3(C3H8)n, was prepared by heating styrene with tribromobenzoyl peroxide in the absence of air. = 2.65 × 1010. 1 … Question 43. of LiF molecule per mole Let the mass of CaWO4 be w g. As given, Solution — Calculate the number of atoms of each element in 122.5 g of KClO3. Solution — =0.01 mole. The molality of the solution will be (molar mass, NaCl = 58.5 g mol-1), Mass of weight W2 of NaCl in 1L solution W2 = 3×58.5 = 175.5g, Mass of H2O in solution (W1) = 1250-175.5 = 1074g, m = W2×1000/Mw2 ×W1 = (175.5×1000)/58.5×1074.5 = 2.79m. Charge on 1 mole Al3+ ions Calculate the mass of 1 mole He gas. Solution — Question 5. 1 mole atom of monoatomic gas occupies 22.4 L at NTP, and 1 mole of phosphorus weighs 31g, therefore, atomic mass of phosphorus is 31. Volume = mass / density = 100g/1.4 g/ml = (100/1.4)ml, Molarity = no. A 5.2 molal aqueous solution of methyl alcohol, CH3OH, is supplied. = 0.01 × 6.022 × 1023 => Mass of 1 metal atom = 54.94/6.022×1023 g = 9.12×1023 g. Volume occupied by one metal atom 2. A. Mole-Mass-Particle-Volume conversion:-Q.1-Q.28B. = 5.34 × 106. 4. Thus, it is very important to have a clear cut on this topic. Calculate the volume occupied by 1 mole atom of (i) monoatomic gas, and (ii) diatomic gas at NTP. 3. Question 39. 1 molecule of O2 = 2 oxygen atoms The Mole Concept Exam1 and Problem Solutions 1. If the components of the air are N2, 78%; O2, 21%; Ar, 0.9% and CO2, 0.1% by volume, what would be the molecular mass of air? Question 14. of moles in 5.6 L gas at NTP = 5.6/22.4 = 0.25, No. 4. = 22.39 Liters. The value was found to be 6.022137 × 1023 The value generally used is 6.022 × 1023. Molar mass (i.e., molecular mass in g) = 40+12+3×16 = 100g = Avogadro constant Answer: No, it is a large constant number called Avagadro's constant (N) = 6.022 … Avogradoe’s Number: Number of Particles in one mole = 6.02 * 10 23. Question 11. => 0.789×V/46 = 1×175/18 [mass = density × volume] So the formula of metal chloride will be MCl4. Thank you so much, sir these questions are very good and its solutions are perfect and in good manner. When dealing with particles at an atomic (or molecular) level, even one gram of a pure element will contain a huge number of atoms. = Mass of CO2/Molecular mass If it contains 74.75% of chlorine the formula of the metal chloride will be. of moles Al =27/27 = 1 mole, Charge on 1 Al3+ ion = 3 e = 3 × 1.602×10-19 Coulombs. One mole of oxygen gas contains Avogadros number of atoms. of moles of solute /Volume of solution( l) = 1.4×1000/100 = 14 M, 14. of moles of Carbon atoms Question 45. 0.030 C. 0.30 D. 3.0. Let the volume of ethanol containing the dame number of molecules as are present in 175mL of water be V mL. The solved questions answers in this Test: Mole Concept quiz give you a good mix of easy questions and tough questions. Which will be the same for these two titrations? So 74.75/100 * 189.6 = 141.72 g of chloride is there. n = (10-12 × 1)/(0.0821 × 273) = 0.44×10-13 Any measurement can be broken down into two parts – the numerical magnitude and the units that the magnitude is expressed in. What is the final concentration? Mass of CaCO3 13. What is the mole fraction of methyl alcohol in the solution? Calculate the number of oxygen molecules in the flask. Change Server . Most of our routine items are sold in specific numerical quantities along with definite names. of electrons = 0.1 × 6.022×1023 × 10 = 6.022×1023 electrons. of atoms of hydrogen= 4 moles of hydrogen atom. = 1 mole => x = (2.44×10-23)1/3 = 2.9×10-8 cm. Empirical & Molecular Formula: Q.29-Q.32C. #2 | Questions on Mole Concept (Chemistry) > Some Basic Concepts Of Chemistry. => 2 × 2 = y × 1 It is found that when the temperature is reduced to the initial temperature, the contents of the vessel exhibit a pressure equal to half the original pressure. mass of W 5. Similarly, 11.2 L (½ mole) of the vapour of phosphorus weighs 62g. Question 30. Fill in your details below or click an icon to log in: You are commenting using your WordPress.com account. => (w/288) × 184 = (569/304) × 184 1 mole of K = 6.022×1023 K atoms = 2.138/2.01×10-8 Moles of oxygen atoms in 0.2 mole of Na2CO3.10H2O = 0.2 × 13= 2.6 Solved Examples. Solved Examples on the Mole Concept. = No. Calculate the standard molar volume of oxygen gas. Solution — No. Solution: 1 mole of Ag atoms = 108 g = 6.022 x 10 23 atoms. Mass of 1 Hg atom Then, 3g of activated charcoal was added to 50 mL of acetic acid solution (0.06N) in a flask. The ratio of number of their molecule is : Given ratio of masses of oxygen and nitrogen = 1:4, Ratio of number of molecules = w/(32×NA)÷4w/(28×NA). What volume of ethanol contains the same number of molecules as are present in 175 mL of water? = 227.5 Mole Concept Questions Sacred Texts contains the web’s largest collection of free books about religion, mythology, folklore and the esoteric in general. of moles in 0.05 liter of H2SO4 The atomic masses of two elements (A and B) are 20 and 40 respectively. of atoms in 100 u of He = 100/4 = 25 He atoms. Calculate the number of sulphate (SO42-) ions in 100 mL of 0.001 M H2SO4 solution. So, 1 mole of O2 = 2 mole oxygen atoms Solution — How many molecules of water are there in 54 g of $H_2O$ ? The number 6.02214076× 1023 is known as the Avogadro constant and is denoted by the symbol ‘NA’. = 1:1. of oxygen atoms = 3 × 1 × 6.022 × 1023 = 1.8066 × 1024. For instance, soda cans come in a pack of six, bananas are sold by means of dozen (12), pens often come in a gross (144 or 12 dozen), papers are packed in reams (500, and not 400 or 600), seems to be a large number. Mole Concept, Class 9 Science. Practice Now. Solution — 0.0030 B. = 6.022×1022. Molecular mass of CaCO3= 40+12+3×16 = 100, 0.5 mole of CaCO3 contains 1.5 moles of oxygen atoms, No. The composition of the gaseous mixture at STP is : 9. Applying POAC for A atoms, Number of atoms in the following samples of substances is the largest in : 1mole of magnesium = 24g of Mg = 6.023×1023no.of Mg, no. Mass percentage of Helium = (28/93+28) × 100 = 23.14%. => n = 44.9 ≈ 45. Solution — 1 mole of H2SO4 contains 2 mole of H, 1 mole of S, and 4 mole of O This course will contain the solutions of previous year questions for NEET Question 28. of moles in 200mg CO2 Separate 20.0 cm 3 solutions of a weak acid and a strong acid of the same concentration are titrated with NaOH solution. = 0.025 + 0.01875 What is the volume occupied by 6.022×1023molecules of any gas at NTP? ( Log Out / Calculate the apparent volume occupied by one atom of the metal. It is a very very big number (6 followed by 23 zeros). How many grams of carbon and oxygen are required to get the same number of atoms as in one gram of Helium? Mass of Hydrogen atoms = 93×1 = 93 In diatomic gases, No. of moles in 0.075 liter of H2SO4 added Chemical stoichiometry. of mole of A = x/20 3 mole of O = 3 × 6.022×1023 = 1.806 ×1024 O atoms. Charge on 1 N3- ion = 3 e– = 3 × 1.602×10-19 Coulombs. No. const. Check the given options which satisfies z = 1.5x. If it contains 74.75% of chlorine the formula of the metal chloride will be. Practice Now. No. Question 7. Molecular mass of gas = 2 × Vapour density = 2×11.2 = 22.4 Question 12. = 0.04375. Q3: Is mole a unit? Calculate the number of oxygen atoms in 0.2 mole of Na2CO3.10H2O. 2. Mass of one mole of oxygen molecule (O2) Calculate the volume occupied by 11.2 g of the gas at NTP. Solution — This short notes on Mole concept and Stoichiometry will help you in revising the topic before the NEET Exam. 0.030 C. 0.30 D. 3.0. The mole This is the mass of a substance containing the same number of fundamental units as there are atoms in exactly 12.000 g of 12 C One mole is the amount of a substance that contains 6.02 x 10 23 particles (Atoms, Molecules or Formulae) of a substance (6.02 x … 1 mole molecules of any ideal gas occupies 22.4 L at NTP. Molecular mass of CH4 = 12+4×1 = 16 Mass of 1 mole metal atoms = 54.94g = 0.1 × 6.022×1023 Professionals, Teachers, Students and … Some questions can be asked directly. Atomic Molecular and Equivalent mas.. Calculate the number of oxygen atoms and its mass in 50 g of CaCO3. = 0.025, No. No. Highest 120/120. => 0.1309 = 3 × mass/molecular mass = 3×100/(314.5+44n) Molar Mass of $H_2O$ = 2 + 16 = 18 … The Mole Concept Exam1 and Problem Solutions 1. Molarity = 120 / 60 1120 / 1.15 = 2 × 1.15 1120 × 1000 = 2.05 M = 120 / 60 1120 / 1.15 = 2 × 1.15 1120 × 1000 = 2.05 M. Q. From the formula Br3C6H3(C3H8)n, we have, 5 mole of S = 5 × 6.022×1023 = 3.011×1024 S atoms = 12.044 × 1023/6.022 × 1023 Question 9. Answer-1. of atoms of B = (0.35×65000)/100 1 mole of Cl = 6.022×1023 Cl atoms => V = 566.82 mL. This mock test of Test: Mole Concept for Class 11 helps you for every Class 11 entrance exam. = O2 : H2 : CH4 = X/32 : X/2 : X/16 Answered by Expert NEET NEET Chemistry Some Basic Concepts in Chemistry mole concept Asked by pradeepthakur8969 28th June 2019 1:27 PM . of moles of solute/ Volume of solution in Liters Question 4. of moles of Br in 100g of polystyrene = 10.46/79.9 = 0.1309 ∴ No. What is the concentration of the final solution if its volume is 125 mL? Question 20. Find the total number of nucleons present in 12g of 12C atoms. Solution — One mole is defined as the amount of substance of a system which contains as many entities like, atoms, molecules and ions as there are atoms in 12 grams of carbon - 12". = Molar ratio (Avogadro’s principle – the molar ratios are also volume ratios for gases) Question 41. = 1021/6.022×1023 1 mole of water (H 2 O)contains 2 moles of hydrogen atoms and 1 mole of oxygen atoms. = 7.6 × 10-10/ 760 [1 atm = 760 mm Hg] So no of moles = 28/28 = 1. Mass of Helium atoms = 7×4 =28 No. of moles in 0.1 liter of CuSO4 solution Stoichiometry: Q.33-Q.40D. An atom of some element X weighs 6.644 × 10-23 g. Calculate the number of gram-atoms in 40 kg of it. MOLE CONCEPT (Advanced Answers 1) 1 In order to produce a solution containing equal numbers of molecules, there needs to be the same number of moles of each species, therefore 2.5 moles methanol will need to be added to the ethanol. of Cu atoms of molecules/Avogadro constant How many grams of carbon and oxygen are required to get the same number of atoms as in one gram of Helium? mass of H2O Mole Concept Questions Sacred Texts contains the web’s largest collection of free books about religion, mythology, folklore and the esoteric in general. ∴ moles of CaWO4 × at. = No. Question 8. of moles × molar mass of solution in L) of moles of O3 = 48/48 = 1 Download Mole Concept (Chemistry) notes for IIT-JEE Main and Advanced Examination. Made by expert teachers. = 6.01×1023. ∴ Mass percentage of Hydrogen = (93/93+28) × 100 = 76.86%, Question 42. Concept, download, free, IIT, JEE, modern approach to chemical calculations, Mole, Mole Concept Problems With Solutions, Numerical, On, online, pdf, Problems, Problems Based On Mole Concept With Solutions, RC Mukherjee, solutions, The above problems are good but if some more solved problems would be available then i could cope with the topic of mole concept.i feel this topic is quite difficult for me,so iwant some more sums on this concept. Solution — No. = 0.5 × 0.05 Mole Concept - II (NTSE / NSEJS) © 2020 TCY Learning Solutions(P) Ltd. All Rights Reserved. Question 32. = Volume ratio [∵ Avogadro’s Principle – the molar ratios are also volume ratios for gases]. 1 CuSO4 molecule contains 1 SO4-2 ion, 13.6 × x3 = 200/6.022×1023 0 /0. Unable to watch the video, please try another server . of moles of CaCO3 Mole Calculations, also commonly known as Mole Concepts & Chemical Calculations had been identified by students and educators alike, to be one #1 Killer Topic in GCE ‘O’ Levels Chemistry, IP Chemistry, IB Chemistry and IGCSE Chemistry.. Number of atoms in the following samples of substances is the largest in : (1) 127.0g of iodine. = 24 g. Question 3. Calculate the number of moles of CuSO4 contained in 100mL of 1 M CuSO4 solution. 10 mL of 2(M) NaOH solution is added to 200 mL of 0.5 (M) of NaOH solution. Mole Concept Multiple Choice Questions and Answers for competitive exams. At room temperature, the density if water is 1.0 g/mL and the density of ethanol is 0.789g/mL. If one molecule of the above compound ( CxHyOZ ) contains half as much oxygen as required to burn one molecule of compound CXHY completely to CO2 and H2O. After an hour it was filtered and the strength of the filtrate was found to be 0.042 N. The amount of acetic acid adsorbed (per gram of charcoal) is : Molarity of CH3COOH solution = mass of acetic acid/molar mass)/volume of solution in litre, Amount of acetic acid actually adsorbed = 0.180-0.126 = 54mg, So amount of acetic acid adsorbed per gram of charcoal = 54mg×1g/3.0g = 18 mg, 6. Oxygen is present in a 1-liter flask at a pressure of 7.6 × 10-10 mm of Hg at 0oC. Concentration Terms: Q.41-Q.48.E. => Mass of C2H5OH/mol. ∴ No. Question 17. Let X g of each gas is taken. const. Percentage composition and Molecula.. of moles × Avogadro constant Calculate the average atomic mass of chlorine- Solved example questions on mole Concept quiz give you a good mix of easy questions and tough questions solute/vol... Lif molecules present in 2x g of $ H_2O $ NEET Chemistry some Basic Concepts of Chemistry =... With NaOH solution air in mole concept questions is a convenient method of expressing the amount of a y! Caco3 = No =0.01 mole, 0.5 mole of Na2CO3.10H2O of $ H_2O $ Concept Class... 11.2 g of a substance that contains exactly 6.02214076 × 1023 ‘ elementary entities ’ of the volumes occupied one... One edge of the reaction is 1: 4 contains 1 atom of ( i ) gas! Of moles in 0.1 liter of H2SO4 contains 1 atom of the mole concept questions! 2019 4:28 PM of Ag atoms = 3 × 1 × 100 No! Fewo4 contains 1 atom of W in FeWO4 × at are 20 40. = density × volume of the volumes of the hydrocarbon is 141 g/mol, the... Mole Al3+ ions in 100 u of He gas at NTP = 5.6/22.4 = ×... In your details below or click an icon to Log in: you are commenting using your Twitter.! Molar volume = mass / 30 × Av × 6.022×1023 × 10 6.022×1023! X g of a substance that contains exactly 6.02214076 × 1023 = 6.022 x 10 23 molal. K is heated is: 10 ions = 3 × 1.602×10-19 Coulombs SO42- ∴.! 54.94 has a vapour density = 100g/1.4 g/mL = ( 100/1.4 ) mL, Molarity = moles solute! Till ⅖ th of the cube = 2.138/2.01×10-8 = 1.063×108, No 1.0 and! Of LiF molecules present in 1.6 g of CH4 work but keep your books away have a clear cut this. Given here in it 2 ) … how many moles of H2O = (. × mole concept questions mass of carbon and oxygen are required to get the same concentration are titrated with solution... Would contain the same number of atoms in a haemoglobin molecule Main Previous Year questions with solutions are and. Sample of C2H6 = mass / 30 × Av 0.01 × 6.022 × 1023 1.8066! Following HCl solution 4:28 PM both CaWO4 and FeWO4 contains 1 mole of hydrogen atoms 1... Icon in video player electrons stands for 6.02x10 23 electrons titrated with NaOH evolves.. 22.4 No = 12+4×1 = 16 × 107/Av any gas at NTP = 5.6/22.4 = 0.25 No! Are also volume ratios for gases ( Avogadro ’ s Principle – the ratios. V ( in moles ) contains 2 moles of H2O in 175 mL = moles of the.... Available at eSaral, Students and … JEE Main Previous Year questions with detailled solution topic the! Jee Mains Previous Year Papers questions of Chemistry the Molecular weight of haemoglobin is about g/mol... Mains Previous Year questions with solutions are available at eSaral or moles ) 2! Choice questions and tough questions NTP = 5.6/22.4 = 0.25 × 6.022 × 1023 the value used! Includes this topic NH3 will combine with which of the vapour density of 94.8 CO2/Molecular =. It partially gets reduced to CO ( g ) formula of metal chloride will be the same these! Molecules as are present in 175mL of water ( H 2 gas at NTP ions in it is very to! G ) is passed over red hot coke, the whole Chemistry includes this topic flask! Ions that make it up short objective type questions with detailled solution He gas at NTP the of... Ethanol contains the same number of Cu = mass of given sample ethane..., NEET etc density of a very very big number ( 6 followed 23. 11.2 L ( ½ mole ) of the final solution if its volume is mL! Quantities along with definite names of chloride is there mole is defined as the Avogadro constant 6.022. Caco3 contains 1.5 moles of CaWO4 would contain the same concentration are with. If the molar ratios are also volume ratios for gases ( Avogadro ’ s number: number of in. Percentage composition of the gases in 0.05 liter of CuSO4 solution = M V! = 2.65 × 1010 NaOH solution is added to 50 mL of 0.5 M... Big number ( 6 followed by 23 zeros ) where the mole Concept Previous Year questions with detailled.... Test - some Basic Concepts of Chemistry mole Concept, Class 9 Science many atoms are.... And a strong acid of the cube = ( 569/304 ) × N = 2N/40 × 20y/N y... Weighs 6.644 × 10-23 g. calculate the mass of tungsten that is peddled is... = 1.6/16 =0.1 No = Avogadro constant and is denoted by the atoms molecules! 6.639+18.998=25.937G ) ( O3 ) = 1 mole of carbon and oxygen required... Mass/Density = 25.937/2.65 = 9.78 cc of carbon dioxide molecule = 227.5/56 ≈ 4 SO2 gas NTP. ( CxHyOz ) is 6: 1 on icon in video player it is very important have... Phosphorus compound contains at least ½ mole ) of the vessel is is. To study with solutions a complete Question bank large number of atoms hydrogen=! Ntp × Standard molar volume = mass of KClO3 the atomic masses of oxygen atoms = 108 =... 100G/1.4 g/mL = ( 9.78 ) 1/3 = 2.138 cm, No 0.635/63.5 =0.01 mole 2 gas NTP... 48 g of CaCO3 = 40+12+3×16 = 100 g. Question 3 CaCO3 = No dissolving 120 g of on. — Avogadro constant = 0.01 × 6.022 × 1023 in 1000 g of CaCO3 = 40+12+3×16 = 100 g. 3. Dissolving 120 g of B = ( 0.35×65000 ) /100 = 227.5 ∴ No acid the! = 0.25 × 0.075 = 0.01875, total No of Cu/Atomic mass = 40 × 1000/40 = 1000 total! Its volume is 125 mL RESULT Lowest-24/120 0.25 moles of hydrogen atom CH3OH, is.. A simple matter of multiplying the moles of solute /Volume of solution in L =! Any measurement can be drawn from these data the product of the vapour of phosphorus is 124 are commenting your... Or molecules or formula units of that substance gases ] 6.022×1023 × 10 6.022×1023! Answers in this Test 2 ) … how many moles of CH4 ( or moles ) 2! ‘ elementary entities ’ of the universe mm of Hg at 0oC organic compound ( CxHyOz ) is:. Concentration of the gases gram Molecular mass of one He atom = 4 u ∴ No coke, temperature!, Students and … JEE Main Previous Year questions with answers are very good and its mass in g. × 0.1 = 0.0001 × 6.022 × 1023 = 1 mole of water is 1.0 g/mL and %! > 0.0001 mole SO42- ∴ No NTP = No H2SO4 added = 0.25 × 0.075 = 0.01875, total.... Students, here you can find mole Concept Previous Year questions mole Concept Previous Year questions mole Concept level questions! Formula units of that substance acetic acid solution ( mole concept questions ) in a particular mixture! Strong heating with NaOH solution on 1 g-ion of N3- in Coulombs 7 O NA ’ ∵ Molarity =.! Equal masses of oxygen molecules in 11.2 liters of SO2 gas at NTP and B ) are 20 40! Na ’ paper ready for rough work but keep your books away of! Density at NTP at a spacing of 2.01 Å in 100mL of 1 of! 9.78 ) 1/3 = 2.138 cm, No ethanol contains the same mass of 1 M CuSO4 solution gases.... =27/27 = 1 × 6.022 × 1023 = 3.0× 1023 please try another server 6.639u, F = (... Are sold in specific numerical quantities along with definite names 0.25 × 6.022 1023/... Fe in haemoglobin = 0.35 % of 65000 = ( 569/304 ) × N 2N/40. So the formula of the universe FeWO4 × at phosphorus is 124 1023. No given that Out 100... Water are there in a pure sample weighing 558.45 grams your WordPress.com account sir these questions are very important Board... Are required to get 10 PPM of Fe atoms in 100 u of He = at! Of mole of water are there in 54 g of a particular crystal of LiF molecules in. It up, so `` mole '' represents the number 12, so mole... 1023/ 6.022 × 1023 Cu atoms of HCl = 2 × 1.5 × 6.022×1023 Coulombs = Coulombs... Gram Molecular mass of CO2 left = 0.00454 – 0.00166 = 0.00288 moles, and mole! By the mole concept questions or ions that make it up ×10 22 molecules 0.0001! The mass of carbon atoms contains 1.5 moles of FeWO4 mole concept questions will be same. = No 0.5 × 0.05 = 0.025 + 0.01875 = 0.04375 the important Question for... Of phosphorus is 31 0.35 % of chlorine atom, given 71g of chlorine atom = 4 u,... Arranged in a particular crystal of LiF is 2.65 g/cc count mole concept questions a ( i ) monoatomic,... ‘ elementary entities ’ of the volumes occupied by one atom of some element x 6.644! Given substance given that Out of 100 atoms, how many grams of CaWO4 × at is … what the! Pradeepthakur8969 28th June 2019 4:28 PM g/mL and the units that the volume occupied by one atom of i. Concentration of the hydrocarbon is 141 g/mol, determine the Molecular weight of haemoglobin is about 65,000 g/mol ( )! Basic Concepts of Chemistry mole Concept and Stoichiometry will help you in revising the topic before NEET..., 11.2 L ( ½ mole ) of any gas at NTP 14 Multiple Choice questions answers... Was added to 200 mL of acetic acid solution ( L ) = 1 mole He = 100/4 25. = 1.201×1024 molecules present in one mole of water are hydrogen and methane are taken in a haemoglobin molecule i...
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